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Sigma notation 123 100 Make generalised formula for this 1+2+3+ till +99+100= 123 100 Given that N = {1, 2, 3, , 100} Then write the subset of N whose element are perfect square numbers

123 100 10100 written long-hand would be 1 with 100 0's × 2 × 1 For example: 5! = 5 × 4 × 3 × 2 × 1 = 120 10! = 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1